ELEC207代写、matlab设计编程代做

日期：2024-04-18 10:10

ELEC207 Coursework (v6: 1 February 2022)

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ELEC207 Coursework: Design of a Stable Martian Segway (“Experiment 81”)

Prof Simon Maskell 1 February 2022

Module ELEC207

Coursework name Experiment 81

Component Weight 25% = 3.75 Credits

Semester 2

HE Level 5

Lab location Third floor EEE building

Work Individually

Timetabled time Check Canvas announcements for lab module

Suggested Private Study time 16h

Assessment method Individual report

Submission Format On line submission - Canvas

Late Submission Standard University Penalties

Resit Opportunity By arrangement

Marking Policy Numerical mark

Anonymous marking Yes

Feedback Canvas

Subject of relevance Control Engineering

AHEP Learning Outcomes LO1

This coursework component1 of ELEC207 relates to Part B, “Control”, and focuses on the

content up to and including lecture 10 of Part B of the module. The mark you will receive for

the coursework constitutes 25% of your mark for ELEC207 and is intended to enable you to

demonstrate your understanding of how to:

? use the position of poles to demonstrate whether systems are stable;

? use your knowledge of control to define a controller that ensures that a system is

stable;

? use root locus to ensure the closed-loop time-response has specific properties;

? use Simulink to validate that the closed-loop time-response is as expected;

? explain your work in a clear and concise fashion.

You are expected to make use of the lecture notes and explicit references to numbered

lectures are therefore included in this document. The demonstrators associated with the lab

are available to support you in undertaking this coursework. Queries can also be submitted

via the discussion board for ELEC207 on Canvas.

The mark you will receive (out of a total of 40 marks) will quantify the following aspects of

your write-up:

? Demonstration of your understanding of ELEC207 (75% and out of 30 marks);

? Clarity of exposition (25% and out of 10 marks).

The marking descriptors are provided in the appendix.

1 Assessment of ELEC207 has previously included Experiment 81, which may result in some legacy references

to experiment 81 in documentation that has not yet been updated to reflect the change. This coursework

takes the place of experiment 81.

ELEC207 Coursework (v6: 1 February 2022)

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Any emboldened text in a box herein implies that a specific response should be included in

your write-up with the number in brackets indicating the number of marks associated with

that component of the write-up. Failure to include such a response is liable to result in you

obtaining fewer marks than would have been the case otherwise.

The assessment of the assignment is intended to be sufficiently straightforward that a

diligent student should be able to achieve a pass mark of 40% but sufficiently challenging

that achieving a first (ie 70% or above) requires deep understanding of the subject matter.

To aid you in understanding how challenging each mark is to obtain, marks are annotated

with E for Easy, M for Moderate and H for Hard: 8 of the marks are deemed to be easy; 14

are deemed moderate; 8 are deemed hard.

You should submit your coursework on or before the deadline announced by the lab

coordinator (check Canvas announcements).

Plagiarism and collusion or fabrication of data is always treated seriously and action

appropriate to the circumstances is always taken. The procedure followed by the University

in all cases where plagiarism, collusion or fabrication is suspected is detailed in the

University’s Policy for Dealing with Plagiarism, Collusion and Fabrication of Data, Code of

Practice on Assessment, Category C, available on:

https://www.liverpool.ac.uk/media/livacuk/tqsd/code-of-practice-onassessment/appendix_L_cop_assess.pdf

ELEC207 Coursework (v6: 1 February 2022)

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1. Mathematical Modelling

A Segway (as shown in figure 1) is a physical system that can be modelled as an inverted

pendulum.

Figure 1: A Segway

More specifically, we will assume that the pendulum can be approximated as a point mass,

of mass m, at a distance, l, and at a (small) angle, θ(t), defined clockwise from vertical.

Gravity is assumed to act downwards and exert an acceleration of g. A motor provides a

torque, T(t). The actuator that converts the Torque control signal to the physical Torque can

be assumed to have a gain of unity. The angular acceleration of the pendulum can then be

approximated as being defined by:

??

??

θ(t) + T(t) = ??

??

2θ(t)

????

2

Our task as an engineer designing the controller for the Martian Segway is to optimise the

time-response to changes to an input, X(t), which defines the desired values for θ(t). We will

consider this design criterion to be achieved if the settling time is equal to ts.

To ensure your Martian Segway is as unique as your coursework, please assume that:

? l is the day of the month when you were born (where l is in metres);

? m is the month of the year when you were born (where m is in kg);

? ts is the year when you were born divided by 250 (where ts is in seconds).

Please define the values for l, m and ts that you will use for your coursework. [1E]

Now derive the transfer function, ??(??) = ??(??)???(??), of the Segway in terms of l, m and

g. [1E]

Using your values for l and m along with g=3.711 ms-2

, write the transfer function with

the denominator and numerator of your transfer function in polynomial form. [1E]

Calculate the position of the poles for your Segway and plot the poles on the complex

plane. [1E]

ELEC207 Coursework (v6: 1 February 2022)

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2. Validating that the Open-loop System is Unstable

With no controller, the system is believed to be unstable. We can use Simulink to validate

this. Open MATLAB R2020a or later (as available using Apps Anywhere or the Remote

Teaching Centre Service2

) and then click Simulink. Information is available online (at:

https://uk.mathworks.com/help/simulink) on how to use Simulink (please also check the

supporting materials available in your Canvas lab module page). Here we provide a brief

description of what is needed for our purposes:

1. Press “Blank Model”;

2. Click the “Library Browser” button, ;

3. Search for a step function by entering “Step” into the box where it says “enter search

term”;

4. Drag and drop the “Step” block onto the Simulink Editor;

5. Click the “Library Browser” button again;

6. Search for “Transfer Fcn” and drag and drop the “Transfer Fcn” block onto the

Simulink Editor. Be careful to select the continuous-time transfer function block

(parameterised by s) and not the discrete-time transfer function block (parameterised

by z);

7. Double click the “Transfer Fcn” block on the Simulink Editor and enter the

polynomials that you calculated above. Be careful that any coefficients of zero need

to be explicitly entered (ie coefficients of [1 0 2] describe s

2+2 but coefficients of [1 2]

describe s+2);

8. Click on the triangle on the right of the “Step” block such that an arrow appears;

9. Connect the output signal from the “Step” block to the input signal for the “Transfer

Fcn” block;

10. Add an “Outport” block;

11. Connect the output signal from the “Transfer Fcn” block to the input signal for the

“Outport” block;

12. Selecting the signal that connects the “Transfer Fcn” block to the input for the

“Outport” block such that it turns blue;

13. Click “Add viewer” (under “Simulation” and “Prepare”) and select “Scope”;

14. Press “Run” (under “Simulation” and “Simulate”). You should now see a graph

showing the time-response of your Segway to a unit-step.

15. Press “File” -> “Print” -> “Microsoft Print to PDF” -> “OK” and save the time-response

to a convenient location.

Insert a picture of the time-response of your Segway to the unit-step. [2E]

Comment on whether this time-response indicates that the open-loop system is

stable. [1M]

3. Ensuring that the Closed-loop System is Stable Using PID Control

We will now add a cascade controller, as explained in lecture 7. We will use a combination of

Proportional, Integral and Derivative control, ie a PID controller. The transfer function of a

PID controller is:

2 You can also download a copy of Matlab/Simulink from the University’s Computer Services Department

website at https://www.liverpool.ac.uk/csd/software/software-downloads/#matlab

ELEC207 Coursework (v6: 1 February 2022)

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??(??) = ???? +

????

??

+ ?????? =

?????? + ???? + ??????

2

??

where Kp, KI and KD are respectively the proportional, integral and derivative control

constants. We know that the closed-loop transfer function for a negative feedback system

with open-loop transfer function of C(s)H(s) and that relates the input, X(s), to the output,

θ(s), is:

??(??)

??(??)

=

??(??)??(??)

1 + ??(??)??(??)

Write the closed-loop transfer function for your Segway in terms of Kp, KI and KD as a

ratio of polynomials in s. Ensure that the highest order term in s in the denominator

has a coefficient of unity. [3M]

To ensure that the system is stable, we start by placing the poles at s=-1, s=-2 and s=-3.

What is the characteristic polynomial that would result in these pole positions? [1M]

By equating the coefficients in the closed-loop transfer function’s denominator and

this characteristic function, deduce values for Kp, KI and KDwhich will ensure that the

closed-loop system is stable. [3M]

4. Validating That the Closed-loop System is Stable

Simulink includes a “Subtract” block and a “PID” block. Use these blocks (with the

parameters of the PID controller that you have defined) to simulate the time-response from a

stable closed-loop system.

Insert a picture of the time-response of your closed-loop system to the unit-step. [2M]

5. Optimising the Time-Response Using Root Locus

The open-loop system has poles and zeros that are the union of those associated with the

plant and those associated with the PID controller.

Calculate the positions of the open-loop zeros (ie the zeros of ??(??)??(??)) for the values

of l, m, Kp, KI and KD that you have used. [1M]

Recall that the PID controller has a pole at the origin and the Segway has poles that you

have calculated above.

State the positions of the open-loop poles (ie the poles of ??(??)??(??)) for the values of l

and m that you have used. [2E]

We are going to use the root locus to choose the open-loop gain to achieve the timeresponse we want. More specifically, we are going to move the closed-loop poles along the

root locus such that we can achieve the settling time that you have defined at the start of this

coursework assignment.

As explained in lecture 6, the settling time for a generalised second-order system with

natural frequency, β, and damping coefficient, ω, is ???? ≈ 4?β??. As explained in lecture 5, the

real part of the location of the poles of a generalised second-order system is ????(??) = ?β??.

We therefore want to ensure that the dominant poles (the poles that are closest to the

ELEC207 Coursework (v6: 1 February 2022)

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imaginary axis) are located such that ????(??) = ? 4 ?? ? ??

. We can understand how to achieve

this by sketching the root locus for the open-loop system with the compensator.

Sketch the root locus for ??(??)??(??) and identify the points on the root locus that are

such that ????(??) = ? ???????

. [3M]

We now want to calculate the value of the open-loop gain that will ensure that the closedloop poles are such that we achieve the desired time-response.

Write the open-loop transfer function, ??(??)??(??), as a ratio of polynomials in ??. [1H]

If the numerator of the open-loop transfer function is ??(??) and the denominator of the openloop transfer function is ??(??), ie ??(??)??(??) = ??(??)???(??), then the closed-loop poles occur

when ??(??) + ????(??) = 0.

Write ??(??) + ????(??) = ?? as a polynomial in ?? involving ??. [1H]

To identify the value of ??, we need to re-express this polynomial as a polynomial in ???= ?? +

4 ?? ? ??

. We can achieve this by substituting ?? = ???? 4 ?? ? ??

(using your value for ????

) and

simplifying.

Write ??(???) + ????(???) = ?? as a polynomial in ??? involving ??. [1H]

As explained in lecture 9, we can then use Routh-Hurwitz to deduce the value of ?? that is

such that ???is on the imaginary axis (ie when ????(??) = ? 4 ?? ? ?? and so we achieve our desired

time-response). We achieve this by choosing ?? to be such that there is a row of zeros.

Complete a Routh table for ??(???) + ????(???). Deduce the value of ?? that is such that

????(??) = ? ???????

[3H]

6. Validating the Response of Optimised System

You can now use Simulink to simulate the time-response from the closed-loop system with

the gain you have chosen, ??. Note that there is a “Gain” block that you may find useful.

Insert a picture of the time-response of your improved closed-loop system to the unitstep. [2H]

7. Further Directions for Private Study (Not Assessed)

Should you find this coursework assignment interesting and wish to continue to work on

designing a Martian Segway, it might be interesting to consider:

1) Using a compensator (eg a PD controller) to ensure that the overshoot adheres to

some design criterion;

2) Using a further compensator (eg a PI controller) to ensure that the steady-state error

is reduced.

For the avoidance of doubt, your mark for the coursework will not be affected by whether you

design these compensators.

ELEC207 Coursework (v6: 1 February 2022)

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Marking descriptors

Demonstration of your

understanding of ELEC207 (75%)

Exposition and structure of the

report (25%)

90-100%

‘Outstanding’

Total coverage of the experiment aims,

objectives and task set. An exceptional

demonstration of knowledge and understanding,

appropriately grounded in theory and relevant

literature. Outstanding research and academic

content.

Extremely clear exposition. Excellently logical

structure. Excellent presentation, only the

most insignificant errors. Scientific

dissemination.

80-89%

‘Excellent’

As ‘Outstanding’ but with some minor

weaknesses in knowledge. Original and novel

aspects presented but not fully developed.

As ‘Outstanding’ but with some minor

weaknesses in structure, logic and/or

presentation.

70-79%

‘Very Good’

Full coverage of the task set. A very good

demonstration of knowledge and understanding

but with some modest gaps. A very good

grounding in theory.

Very clear exposition. Satisfactory structure.

Very good presentation, largely free of

grammatical and other errors. All compulsory

sections present.

60-69%

‘Comprehensive’

As ‘Very Good’ but with some gaps in knowledge

and understanding and/or gaps in theoretical

grounding.

As ‘Very Good’ but with some weaknesses in

exposition and/or structure, a few more

grammatical and other errors.

50-59%

‘Competent’

Covers most of the task set. Patchy knowledge

and understanding with a limited grounding in

literature.

Competent exposition and structure.

Competent presentation but some significant

grammatical and other errors. Minor errors

in labelling graphs and figures.

40-49%

‘Adequate’

As ‘Competent’ but patchy coverage of the task

set and more weaknesses and/or omissions in

knowledge and understanding. Just meets the

threshold level.

As ‘Competent’ but with more weaknesses in

exposition, structure, presentation and/or

errors. Just meets the threshold level.

35-39%

‘Compensatable

fail’

Some parts of the set task are likely to have been

omitted. Major gaps in knowledge and

understanding. Some significant confusion. Very

limited grounding. Falls just short of the

threshold level.

Somewhat confused and limited exposition.

Confused structure. Some weaknesses in

presentation and some serious grammatical

and other errors. Falls just short of the

threshold level.

20-34%

‘Deficient’

As ‘Compensatable Fail’ but with more serious

weaknesses in presentation and/or grammar.

Falls substantially below the threshold level.

As ‘Compensatable Fail’ but with more

serious weaknesses in presentation and/or

grammar. Falls substantially below the

threshold level.

0-20%

‘Extremely weak’

Largely confusing exposition and structure. Many

serious grammatical and other errors.

Largely confusing exposition and structure.

Many serious grammatical and other errors.