代做COMP122编程、java程序代写调试、Java编程语言代写

日期：2021-03-06 11:03

COMP122 Assessment 1 Due 2021-03-05 at 5pm

The Caesar Cipher

The Caesar cipher is an ancient method of encrypting text, i.e. to transform text into a format that is

unreadable for anyone without a secret key. It is believed that Julius Caesar actually used such a cipher

for his correspondence. Unfortunately for him, This type of cipher is easily broken using a frequency

analysis method outlined below. Your assignment is to implement this in Java.

Part 1: Encrypting and Decrypting

The Caesar cipher is a “rotation cipher” and operates by translating each letter into the one that is

shied along the alphabet by a fixed distance. This distance is called the shi. It is the same for all

letters in the alphabet and therefore can be seen as the secret key to encrypt and decrypt: To encrypt

your text using a given shi, you translate letters by that many places later in the alphabet. A Caesar

cipher with shi 3 can be illustrated as follows.

For example, if your text to encrypt is “Meet me at midnight under the bridge” and your shi is 3, the

encrypted text is “Phhw ph dw plgqljkw xqghu wkh eulgjh”, as the letter “b” gets translated into an “e”,

and “e” gets translated into “h” and so on. We “wrap around” at the end of the alphabet, so that “z”

gets changed to a “c” given a shi of 3. We can interpret a negative value for the shi as translating

letters backwards (e.g. an “f” gets encrypted as the letter “b” if the shi is ?4).

Requirements

In a file called Caesar.java, implement the following (public static) methods.

? a method called rotate that rotates a single character. It should have two arguments: an integer

(int) shi and a char to rotate, and return the character rotated by the given shi, as a char.

Lower-case characters should be translated into lower-case characters, capitalised ones into

capitalised ones, and all other characters should remain untouched.

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COMP122 Assessment 1 Due 2021-03-05 at 5pm

? another method called rotate that rotates a whole string. It should have two arguments: an

integer (int) shi and a String to rotate and return the string rotated by the given shi, as a

String.

? a main method, that allows to encode/decode text, as follows. This should interpret the first two

The first argument is interpreted as an integer shi and the second one as a (string) message to

be rotated. The only output printed by the program should be the rotated string output.

Moreover, the main method should check if it was called with exactly two arguments and complain

otherwise. See below for example outputs. Your program needs to print the exact same

output to be considered correct.

$> java Caesar 3 "The ships hung in the sky in much the same way that bricks don't."

Wkh vklsv kxqj lq wkh vnb lq pxfk wkh vdph zdb wkdw eulfnv grq'w.

$> java Caesar -13 "The ships hung in the sky in much the same way that bricks don't."

Gur fuvcf uhat va gur fxl va zhpu gur fnzr jnl gung oevpxf qba'g

$> java Caesar 13 The ships hung in the sky in much the same way that bricks don't.

Too many parameters!

Usage: java Caesar n "cipher text"

$> java Caesar 13

Too few parameters!

Usage: java Caesar n "cipher text"

Part 2: Cracking the Caesar cipher.

Suppose we are given a cipher text, i.e. text that has already been encrypted with some (unknown)

shi, and we want to determine the original unencrypted text (typically referred to as the plaintext).

To reconstruct the original text we could decode with each of the 26 possible shis, and take the result

that looks “closest” to an English sentence.

How do we measure “closeness”? This is where letter frequencies and a small statistical trick comes in.

First of all, we know how oen each letter occurs on average in English text. For instance, “e” is the

most common letter, then “t”, and so on. To decode our cipher text, we can compute the frequencies

of each letter as they appear in the text. To measure how “close” these are to the known English letter

frequencies, we use the χ

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-score (that is the Greek letter “chi”, so it’s the “chi-squared score”). This

score is defined as

χ

2 =

Xz

α=a

(freqα ? Englishα

)

2

Englishα

where freqα denotes the frequency of a letter α (the number of occurrences divided by the total number

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COMP122 Assessment 1 Due 2021-03-05 at 5pm

of letters in the text), and Englishα

is the corresponding English letter frequency. In other words, we

sum the fraction over all 26 possible letters to determine this score, which is a single number.

The χ

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score will be lower when the frequencies are closer to English. Note that when we do this, we

are ignoring the case of letters (we want to treat upper and lower case equally for our purposes).

You are provided with a file called Brutus.java, which already defines letter frequencies in English

texts. This is given as array of doubles, in alphabetical order:

1 public static final double[] english = {

2 0.0855, 0.0160, 0.0316, 0.0387, 0.1210, 0.0218, 0.0209, 0.0496, 0.0733,

3 0.0022, 0.0081, 0.0421, 0.0253, 0.0717, 0.0747, 0.0207, 0.0010, 0.0633,

4 0.0673, 0.0894, 0.0268, 0.0106, 0.0183, 0.0019, 0.0172, 0.0011

5 };

Accordingly, the frequency of the letter “a”, the probability that a randomly chosen letter in an English

text is an “a”, is Englisha = 0.0855 and can be accessed as english[0]. Similarly, Englishb = 0.0160

and so on.

Requirements

In Brutus.java, write

? a method called count that takes a single String parameter and returns a length-26 integer

array whose values reflect how oen each character occurred. You should not make a dierence

between upper and lower case letters and the returned array should be in alphabetical order.

This way, if letterCounts is an array resulting from your method then letterCounts[25] is

the number of times the letter “z” or “Z” occurs.

? a method called frequency that takes a single String and returns a length-26 array of double

s whose values correspond, in alphabetical order, to the frequency of the letter. This way, if

letterFreq is an array resulting from this method then letterFreq[24] is the number of

times the letter “x” or “X” occurs, divided by the length of the string input.

? a method called chiSquared, which returns the χ

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-score (a double) for two given sets of

frequencies. That is, it should take two parameters, both of type double[], and return a single

double value that tells us how close these two arrays are. You may assume that the two inputs

are always of length 26.

? a main method that can be used to decipher Caesar-encoded English cryptotext without the

key. Of course, you should be using your chiSquared method as well as the given English letter

frequencies.

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COMP122 Assessment 1 Due 2021-03-05 at 5pm

The string that is to be deciphered should be read from the first command line argument and

your program should ensure that it gets exactly this one argument and complain otherwise.

Sample output below.

$> java Brutus "Vg vf n zvfgnxr gb guvax lbh pna fbyir nal znwbe ceboyrzf whfg jvgu

cbgngbrf."

It is a mistake to think you can solve any major problems just with potatoes.

$> java Brutus

Too few parameters!

Usage: java Brutus "cipher text"

$> java Brutus Too Many Parameters

Too many parameters!

Usage: java Brutus "cipher text"

Hints and Comments

1. In Java, char and int variables are (more or less) interchangeable. A Java statement like

1 int diff = 'e' - 'b';

is perfectly legal, i.e. Java can interpret the “dierence of two letters” with no problem, and

this will give an integer value. If the two letters are of the same case, then this will give a value

between ?25 and 25. In particular, if ch is a lower case (char) letter, then

1 int diff = ch - 'a';

tells you how many places aer ‘a’ that letter is in the alphabet. (The value of diff will be

between 0 and 25 inclusive).

2. When translating letters, notice that if ch-'a' is between 0 and 25 (inclusive), then ch is a lower

case letter, and we encrypt as above. Alternatively, if ch-'A' is between 0 and 25 (inclusive), we

encrypt ch similarly to get a new upper case letter. You may also use helper methods isLetter,

isLowerCase etc from the Character class.

3. In order to translate whole strings, recall that you can access the individual characters in a string

using the charAt method: if str is a String then str.charAt(i) gives you the char at index

i in str.

4. When counting letter frequencies remember that for this exercise, we consider upper and lower

case to be the same and do not consider spaces and punctuation characters. For example, in the

string "Mississippi moon!", the frequency of the letter “m” is 2/15, while the frequency of

the letter “s” is 4/15.

5. Make sure you that your code is readable and appropriately documented. There will be points for

javadoc comments that explain what each method does and how its parameters are interpreted.

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COMP122 Assessment 1 Due 2021-03-05 at 5pm

6. You can run a (partial) automarker to check that your submission is in the correct format.

$> check50 liv-ac-uk/comp122/2021/problems/caesar

Submission

Submit you solution using submit50 just like the lab exercises.

$> submit50 liv-ac-uk/comp122/2021/problems/caesar

You can submit multiple times and only the latest version (and it’s submission time) will be considered

for grading.

Submissions are subject to UoL’s Code of Practice on Assessment and the usual late penalties (-5% per

for each 24 hour period immediately following the deadline) apply. If you require an extension due to

extenuating circumstances please get in touch with the CS student oice (csstudy@liv.ac.uk) before

the submission deadline. We will not grant any extensions aerwards.

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